Составь двойное неравенство,которому удовлетворяют все эти числа: 2058, 2508, 5028, 5082, 5208, 5802, 8052, 8502.

8205,может быть так я не знаю

12/3 - b = 5/6 b = 1 2/3 - 5/6b = 1 4/6 - 5/6b = 5/67/12 + a = 1 1/6 a = 1 1/6 - 7/12 a = 1 2/12 - 7/12 a = 7/12 y * 2/7 = 3/14y = 3/14 : 2/7у = 3/14 * 7/2у = 3/4 6/7 : c = 3/14с = 6/7 : 3/14с = 6/7 *  14/3с = 4 c + 1 1/3 = 3с = 3 - 1 1/3с = 1 2/3 a : 2/3 = 3/4а = 3/4 * 2/3а = 1/2 y - 5/6 = 1/3у = 1/3 + 5/6 у = 2/6 + 5/6 у = 1 1/6 1 5/6 - y = 2/3 у = 1 5/6 - 2/3 у = 1 5/6 - 4/6 у = 1 1/6 x - 7/10 = 7/10х = 7/10 + 7/10 х = 1 4/10 х = 1 2/5 1/3 +x= 1 1/6х = 1 1/6 - 1/3 х = 1 1/6 - 2/6 х = 5/6 1 1/4 - b = 1/2 b = 1 1/4 - 1/2 b = 1 1/4 - 2/4 b = 3/4 1 1/2 * a = 6a = 6 : 1 1/2  а = 6/1 : 3/2 а = 6/1 * 2/3 а = 4 1 3/4 : x = 7х = 1 3/4 : 7 х = 7/4 : 7/1 х = 7/4 * 1/7 х = 1/4 b * 5/7 = 1b = 1 : 5/7  b = 1/1 * 7/5 b = 7/5 b = 1 2/5 7/8 + a = 1 1/4 а = 1 1/4 - 7/8 а = 1 2/8 - 7/8 а = 3/8 y * 3/5 =  1/15 у = 1/15 : 3/5 у = 1/15 * 5/3 у = 1/9 1 2/3 : y = 5у = 1 2/3 : 5 у = 5/3 : 5/1 у = 5/3 * 1/5 у = 1/3