Диагонали параллелограмма ABCD пересекаются в начале координат. А (-2; 2; -1), В (3; 4; 2). Вычислите координаты других вершин параллелограмма.

Пошаговое объяснение:

Если диагонали параллелограмма ABCD пересекаются в начале координат, то координаты других вершин параллелограмма имеют обратные знаки.

A(-2;2;-1)⇒ С(2;-2;1) 

B(3;4;2) ⇒ Д(-3;-4;-2)

Этот параллелограмм  не является  прямоугольником.

Угол АВ_ВС:

Скалярное произведение а*в = -20,

Модуль а*в = 38,

cos <(a_b) = -0,5263,

<(a_b) = 2,125058161 радиан = 121,757 градуса.

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