Всю первую строку , найти молекуляркую массу и омегу

ответ:

объяснение:

mr(h2s) = 1*2 + 32 = 34

w(h) = ar(h) *n / mr(h2s)   *100% = 1*2 / 34   *100% =6%

w(s) = ar(s) *n / mr(h2s)   *100% = 32 *1 / 34   *100% = 94%

mr(cs2) = 12 + 32*2 =76

w(c) = ar(c) *n / mr(cs2)   *100% = 12*1 / 76   *100% =16%

w(s) = ar(s) *n / mr(cs2)   *100% = 32*2 / 76   *100% = 84%

mr(caso4) = 40 + 32+16*4 =136

w(ca) = ar(ca) *n / mr(caso4)   *100% = 40*1 / 136   *100% =29%

w(s) = ar(s) *n / mr(caso4)   *100% = 32*1 / 136   *100% = 23%

w(o) = ar(o) *n / mr(caso4)   *100% = 16*4 / 136   *100% =48%

mr(na2so4) = 23*2 + 32 + 16*4 =142

w(na) = ar(na) *n / mr(na2so4)   *100% = 23*2 / 142   *100% =32%

w(s) = ar(s) *n / mr(na2so4)   *100% = 32*1 / 142   *100% = 22%

w(o) = ar(o) *n / mr(na2so4)   *100% = 16*4 / 142   *100% = 46%

mr(fe2(so4)3 = 56*2 + 32*3 + 16*12 = 342

w(fe) = ar(fe) *n / mr(fe2(so4)3   *100% = 56*2 / 342   *100% =33%

w(s) = ar(s) *n / mr(fe2(so4)3   *100% = 32*3 / 342   *100% =28%

w(o) = ar(o) *n / mr(fe2(so4)3)   *100% = 16*4 / 342   *100% = 39%

3NaOH + FeCl3 ---> 3NaCl + Fe(OH)3↓

Полное ионное:

3Na⁺ + 3OH⁻ + Fe³⁺ + 3Cl⁻ > 3Na⁺ + 3Cl⁻ + Fe(OH)3

Краткое ионное:

3OH⁻ + Fe³⁺ > Fe(OH)3