Материальная точка движется прямолинейно по закону найти значение времени t, при котором ускорение точки равно 4 м/с². решите подробно, т.к. мне надо будет объяснить как решал, если есть какие нибудь формулы по решению напишите их тоже, ! ​

ответ:

объяснение:   ускорение точки а(t)=v'(t)  

скорость точки v(t)=x'(t)  

x'(t) =1/3*3t^2-3*2t+3=t^2-6t+3=v(t)

v'(t)   =2t-6=а(t)

а(t)=4     2t-6=4     2t=10 t=5

ускорение - есть вторая производная от пути по времени .

по условию ускорение равно 4 м/c²

4 = 2t - 6

2t = 10

t = 5

ответ : ускорение точки равно 4 м/c² в момент времени t = 5 c

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2x²-5x-4=0

a = 2

b = - 5

c = - 4

a)

b)