3. баба копра массой 200 кг падает на сваю с высоты 3 м. какую работу совершает сила тяжести при этом падении.

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Ответы на вопрос:

alaaaaaaaaa

Физика

4,5(80 оценок)

ответ:

а = 5880 дж.

объяснение:

дано:

m = 200 кг

h = 3 м

g = 9.8 $\frac{н}{кг}$

найти:

a - ?

--------------------------------------------------------------------------------------------------------------

решение.

a = fh

} => a = mgh.

f = mg

[a] = кг * $\frac{н}{кг}$ * м = дж.

a = 200 кг * 9.8 $\frac{н}{кг}$ * 3 м = 5880 дж.

Stasya1506

Физика

4,7(40 оценок)

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Объяснение:

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