Ради бога молю вас молю молю молю все привсе мои сколько у меня есть только пишите правильно прашу ​

я считаю так)

1. when were tim and annie to india?

2. i have been here since

3. ok

4. she was a photographer

5. james and i met last march

6. ok

7. john   has been looking for a new

8. did you speak to your

9. i have been playing the guitar

10. what did you do last night?

ртпооаоаьмо вгаьвоьаьсsinx + cos x + sin2x = 1

sin x + cos x + 2sinx cosx -1=0

sin x + cos x +2sinx cosx -(sin²x+cos²x)=0

(sin x + cos x) + 2sinx cos x - (sin²x+cos²x+2sinx cosx -2sinx cos x)=0

(sin x+ cos x)+2sinx cosx - (sin x + cos x)² +2sinx cosx=0

(sin x + cos x)² + (sinx + cosx)+4sinxcosx=0

Пусть sin x + cos x = t причем (-√2 ≤ t ≤ √2), тогда возведем оба части до квадрата, имеем

(sin x + cos x)² = t²

1+2sinx cosx = t²

2sinxcosx = t²-1

Заменяем

t²+t+2*(t²-1)=0

t²+t+2t²-2=0

3t²+t-2=0

D=1+24 = 25

t1=(-1+5)/6=2/3

t2=(-1-5)/6 = -1

Возвращаем к замене

\begin{gathered}\sin x+\cos =-1\\ \sqrt{2} \sin(x+ \frac{\pi}{4} )=-1 \\ \sin(x+ \frac{\pi}{4} )=- \frac{1}{ \sqrt{2} } \\ x+ \frac{\pi}{4}=(-1)^{n+1} \frac{\pi}{4}+ \pi n,n \in Z\\ x=(-1)^{n+1} \frac{\pi}{4}- \frac{\pi}{4}+ \pi n,n \in Z\end{gathered}

sinx+cos=−1

2

sin(x+

4

π

)=−1

sin(x+

4

π

)=−

2

1

x+

4

π

=(−1)

n+1

4

π

+πn,n∈Z

x=(−1)

n+1

4

π

−

4

π

+πn,n∈Z

\begin{gathered}\sin x+\cos x= \frac{2}{3} \\ \sqrt{2} \sin(x+ \frac{\pi}{4})= \frac{2}{3} \\ \sin (x+ \frac{\pi}{4})= \frac{ \sqrt{2} }{3} \\ x=(-1)^n\arcsin( \frac{ \sqrt{2} }{3} )- \frac{\pi}{4}+ \pi n,n \in Z\end{gathered}

sinx+cosx=

3

2

2

sin(x+

4

π

)=

3

2

sin(x+

4

π

)=

3

2

x=(−1)

n

arcsin(

3

2

)−

4

π

+πn,n∈Z