1) cos (a+pi/3) cos a= -15/17 2) sin (a-pi/4) sin a= 0.6 3) sin (a-b) + sin (pi/2-a)*sin b

1. по формуле косинуса суммы: cos(a+π/3)=сos(a)*cos(π/3)-sin(π/3)*sin(a)=cos(a)/2-(√3*sin(a))/2=(cos(√3*sin(/2=(cos(√3*√(1-cos(/2= =(-15/17-(√3*√(1-15/17))/2=-(15+√102/17)/2=7.5+√102/32 2.формула разности синусов sin(a-π/4)=sin(a)*cos(π/4)-sin(π/4)*cos(a)=√2/2*(sin(a)-cos(a)) применив основное тригонометрическое тождество =√2/2*(1-2cos(a))=√2/2-√2*соs(a)=√2/2-√2*√(1-sin(a))= =√2/2-√2*√(1-0.6)=√2/2-(2√5)/5 3. sin(a-b) + sin(π/2-a)*sin(b)= формула суммы синусов sin(a)*cos(b)-sin(b)*cos(a)+(sin(π/2)*cos(a)-sin(a)*cos(π/2))*sinb=sin(a)*(cos(b)-sin(b)*(cos((π/2)*cos(a)-sin(a)*cos(π/2))= sin(a)*cos(b)-sin(b)*(cos((π/2)*cos(a)-sin(a)*cos(π/=sin(a)*cos(b)-sin(b)*(cos(a)-sin(π/2)*cos(a)+sin(a)*cos(π/2))=sin(a)*cos(b)-sin(b)*(cos(a)(1-2*sin(π/2))+cos(π/2)*(sin(a)+cos(a))= =sin(a)*cos(b)-sin(b)*(cos(a)*(1-√2)+√2/2*(sin(a)+cos(a))=sin(a)*cos(b)-sin(b)*(cos(a)-√2/2*cos(a)+√2/2*sin(a)=sin(a)*cos(b)-sin(b)*(cos(a)*(1-√2)+√2/2*(sin(a)+cos(a))=sin(a)*(cos(b)-√2/2*sin((b)*(cos(a)*(1-√2)+√2/2*(cos(=sin(a)*(cos(b)-√2/2*sin((b)*((2-√2)*cos(a))=-sin(b)*((4+√2)/2)+sin(a)*cos(b)-sin(b)*cos(a)=sin(a-b)-sin(b)*((4+√2)/2)

1. 29*38=1102 2. 29*28=812 3. 1102-812=290 4. 36*53=1908 5.36*47=1692 5.58000: 290=200 6.1908+1692=3600 7. 3600-200=3400 ответ: 3400