Нужна блок-схема нарисованная. var i, j, n, min: integer; v: array[1..8]of integer; p: array[1..8]of integer; s: array[1..8]of integer; begin min : = 999; for i : = 1 to 8 do read(v[i]); for i : = 1 to 8 do read(p[i]); for i : = 1 to 8 do read(s[i]); for i : = 1 to 8 do if(p[i] = 0) and (s[i] = 1) and (v[i] < min) then min : = v[i]; write(min); end.

Program massiv_zamena_min_max; uses crt; var massiv: array [1..100,1..100] of integer; i,j,mr,mc,min, max, minj, maxj, tmp: integer; begin clrscr; mr: =101; mc: =101; while ((mr> 100)or(mr< 0)or(mc> 100)or(mc< 0)) do begin writeln('vvedite razmernost massiva (ne bolee chem 100x100): '); readln(mr); readln(mc); end; for i: =1 to mr do for j: =1 to mc do begin writeln('vvedite element massiva nomer ',(i-1)*mc+j,': '); readln(massiv[i,j]); end; writeln('massiv do izmeneniya: '); for i: =1 to mr do begin for j: =1 to mc do write(massiv[i,j],' '); writeln; end; min: =massiv[1,1]; minj: =1; for i: =1 to mr do for j: =1 to mc do if massiv[i,j]begin min: =massiv[i,j]; minj: =j; end; max: =massiv[1,1]; maxj: =1; for i: =1 to mr do for j: =1 to mc do if massiv[i,j]> max then begin max: =massiv[i,j]; maxj: =j; end; for i: =1 to mr do begin tmp: =massiv[i,minj]; massiv[i,minj]: =massiv[i,maxj]; massiv[i,maxj]: =tmp; end; writeln('nomer ctolbca s minimalnym elementom: ',minj); writeln('nomer ctolbca s maximalnym elementom: ',maxj); writeln('massiv posle izmeneniya: '); for i: =1 to mr do begin for j: =1 to mc do write(massiv[i,j],' '); writeln; end; readln; end. это решение

Вк это социальная сеть, а телега месенжер, там из общих только чаты