Сu-cuo-cuso4-ca(oh)2-cucl2 ba - bao- ba(oh)2-bacl2-baso4 al-al2o3-alcl3-al(oh)3-al2(so4)3 ca-cao-ca(oh)2-caco3-cacl2 надо заранее )

2cu+o2=2cuo

cuo+h2so4=cuso4+h2o

cuso4+2koh=cu(oh)2+k2so4

cu(oh)2+2hcl=cucl2+2h2o

2ba+o2=2bao

bao+h2o=ba(oh)2

ba(oh)2+2hcl=bacl2+2h2o

bacl2+h2so4=baso4+2hcl

4al+3o2=2al2o3

al2o3+6hcl=2alcl3+3h2o

alcl3+3koh=al(oh)3+3kcl

al(oh)3+h2so4=al2(so4)3+

2ca+o2=2cao

cao+h2o=ca(oh)2

ca(oh)2+h2co3=caco3+2h2o

caco3+2hcl=cacl2+h2co3

1.   2cu+o2=> 2cuo

cuo+so3=> cuso4

cuso4+2koh=> k2so4+cu(oh)2

2agcl+cu(oh)2=> 2agoh+cucl2

2.   2ba+o2=> 2bao

bao+h2o=> ba(oh)2

ba(oh)2+fecl2=> bacl2+fe(oh)2

bacl2+h2so4=> baso4+2hcl

3.   4al+3o2=> 2al2o3

al2o3+5hcl=> 2alcl3+3h2o

alcl3+3naoh=> al(oh)3+3nacl

2al(oh)3+3h2so4=> al2(so4)3+6h2o

4.   2ca+o2=> 2cao

cao+h2o=> ca(oh)2

ca(oh)2+co2=> caco3+h2o

caco3+2hcl=> cacl2+h2o+co2

ответ:

дано

m(mg) = 36 g

m(h2o)-?

n(mg) = m(mg) / m(mg) * n(a) = 36   / 24 * 6,02*10^23 = 9,03 *10^23

n(mg) = n(h2o) = 9.03*10^23

m(h2o) = 18 g/mol

n(h2o) =( m(h2o) / m(h2o) ) * n(a) * n , n = 3 at

m(h2o) = (n(h2o) *m(h2o) ) / (n(a) * n)

m(h2o) = ( 9.03*10^23 * 18) / (6.02*10^23 * 3) = 9 g

ответ 9 г

объяснение: