Какой объём при нормальных условиях будет порция углекислого газа при массе 8,8 грамм

Решение m(co2)=44г/моль n(co2)=m/m=8.8/44=0.2 v(co2)=n*vm = 22.4*0.2 = 4.48л

Посмотри источник там все превращения с mg)) mg(oh)2 + h3po4 = mg3(po4)2 + h2o3mg(oh)2 + 2h3po4 = mg3(po4)2 + 6h2o mn(no2)2 + becl2=be(no2)2 + mncl2mn(no2)2 + becl2 = be(no2)2 + mncl2 mn(no2)2 + becl2=be(no2)2 + mncl2mn(no2)2 + becl2 = be(no2)2 + mncl2 mno2 + mg = mn + mgomno2 + 2mg = mn + 2mgo mg + h2o = mg(oh)2 + hmg + 2h2o = mg(oh)2 + 2h mg + h2o = mgoh + hmg + h2o = mgoh + h mgso4 + 2naoh = mg(oh)2 + na2so4mgso4 + 2naoh = mg(oh)2 + na2so4 mg(oh)2 + h3po4 = mg3(po4)2 + h2o3mg(oh)2 + 2h3po4 = mg3(po4)2 + 6h2o mg(oh)2 + h3po4 = mg3(po4)2 + h2o3mg(oh)2 + 2h3po4 = mg3(po4)2 + 6h2o mno2(s)+hcl(aq)=cl2(g)+mncl2(aq)+h2o(l)mno2(s) + 4hcl(aq) = cl2(g) + mncl2(aq) + 2h2o(l) mg+cl2=mgcl2mg + cl2 = mgcl2 mg(oh)2 + hcl = mgcl2 + h2omg(oh)2 + 2hcl = mgcl2 + 2h2o mg(oh)2 + hcl = mgcl2 + h2omg(oh)2 + 2hcl = mgcl2 + 2h2o mg + hcl = mgcl2 + h2mg + 2hcl = mgcl2 + h2 mg + hcl = mgcl2 + h2mg + 2hcl = mgcl2 + h2 mg + co2 = mgo + c2mg + co2 = 2mgo + c mno2+hbr=mnbr2+br2+h2omno2 + 4hbr = mnbr2 + br2 + 2h2o mg + h2o = mg(oh)2 + h2mg + 2h2o = mg(oh)2 + h2 mg + h2o = mg(oh)2 + h2mg + 2h2o = mg(oh)2 + h2 mgco3+hno3=mg(no3)2+h2o+co2mgco3 + 2hno3 = mg(no3)2 + h2o + co2 mno2 + pbo2 + h+ = mno4- + pb++ +h2o2mno2 + 3pbo2 + 4h+ = 2mno4- + 3pb++ +2h2o mno2 + pb2 + h+ = mno4- + pb++ +h2o-4mno2 + 3pb2 + 16h+ = -4mno4- + 6pb++ +8h2o mno2 + h2o = mno4- + e- + h+2mno2 + 4h2o = 2mno4- + 3e- + 8h+ mno2 + pbo2 + h+ = mno4- + pb++ +h2o2mno2 + 3pbo2 + 4h+ = 2mno4- + 3pb++ +2h2o mno2+hcl=mncl2+cl2+h2omno2 + 4hcl = mncl2 + cl2 + 2h2o mg(no3)2=mgo+no2+o22mg(no3)2 = 2mgo + 4no2 + o2 mno4- + so3-- +h2o=mno2 + so4-- +oh-2mno4- + 3so3-- +h2o = 2mno2 + 3so4-- +2oh- mno4- + cl- + h+=mn++ +cl++ +h2o3mno4- + 5cl- + 24h+ = 3mn++ +5cl++ +12h2o mgcl2 + agno3 = agcl + mg(no3)2mgcl2 + 2agno3 = 2agcl + mg(no3)2 mg+hcl=mgcl+hmg + hcl = mgcl + h mg + cu(no3)2 = mg(no3)2 + cumg + cu(no3)2 = mg(no3)2 + cu mg + o2 = mgo2mg + o2 = 2mgo mg + p4 = mg3p26mg + p4 = 2mg3p2 mg3n2+h2o=mg(oh)2+2nh3mg3n2 + 6h2o = 3mg(oh)2 + 2nh3 mno4 - +cl- + h+ = mn2+ + cl2 + h2o4mno4- + 26cl- + 32h+ = 2mn2+ + 13cl2 + 16h2o mg(s) + n2(g) = mg3n2(s)3mg(s) + n2(g) = mg3n2(s) mg+n2=mg3n23mg + n2 = mg3n2 mg3n2 + h2o = mg(oh)2 + nh3mg3n2 + 6h2o = 3mg(oh)2 + 2nh3 mg+2h3o+ = h2 + 2h2o + mg+2mg + 2h3o+ = h2 + 2h2o + mg+2 mgcl2 + naoh = mg(oh)2 + naclmgcl2 + 2naoh = mg(oh)2 + 2nacl mn++ +cl2 + h2o = mno2 + cl- + h+mn++ +cl2 + 2h2o = mno2 + 2cl- + 4h+ mg+n2=mg3n23mg + n2 = mg3n2 mgc2o4+2hcl=mgcl2+h2c2o4mgc2o4 + 2hcl = mgcl2 + h2c2o4 mg co3=mgo+co2mgco3 = mgo + co2 mg(oh)2+hcl=mgcl2+h2omg(oh)2 + 2hcl = mgcl2 + 2h2o mgbr2+cl2=mgcl2+br2mgbr2 + cl2 = mgcl2 + br2 mg+o2=mgo2mg + o2 = 2mgo mg + cucl= cu + mgclmg + cucl = cu + mgcl mno2 + hcl = mncl2 + cl2 + h2omno2 + 4hcl = mncl2 + cl2 + 2h2o mn+2 + hbio3 + h+ = mno4-1 + bi+3 + h2o2mn+2 + 5hbio3 + 9h+ = 2mno4-1 + 5bi+3 + 7h2o mno + h+ = mn+2 + h2omno + 2h+ = mn+2 + h2o mn + naoh = mn(oh)2 + namn + 2naoh = mn(oh)2 + 2na mg(oh)2+co2=mgco3+h2omg(oh)2 + co2 = mgco3 + h2o mns + hcl = mn + h2s + clmns + 2hcl = mn + h2s + 2cl mg + hcl = mgcl2 + h2mg + 2hcl = mgcl2 + h2 mg +o2 = mgo2mg + o2 = 2mgo mn + s= mnsmn + s = mns mg + n2 =mgn2mg + n2 = 2mgn mn(no3)2 + ca(clo)2 + naoh = namno4 + nano3 + cacl2 + h2o4mn(no3)2 + 5ca(clo)2 + 12naoh = 4namno4 + 8nano3 + 5cacl2 + 6h2o mno2 + hcl = mncl2 + cl2 + h2omno2 + 4hcl = mncl2 + cl2 + 2h2o ms2+o2=ms2o2ms2 + o2 = 2ms2o mn(oh)2+h2o2=mno2+h2omn(oh)2 + h2o2 = mno2 + 2h2o mgbr2+koh=kbr+mg(oh)2mgbr2 + 2koh = 2kbr + mg(oh)2 mn++ +h+ + pbo2=mno4- + pb++ +h2o2mn++ +4h+ + 5pbo2 = 2mno4- + 5pb++ +2h2o mg (s) + o2 (g)=mgo (s)2mg(s) + o2(g) = 2mgo(s) mg (s) + o2 (g)=mgo (s)2mg(s) + o2(g) = 2mgo(s) mg (s) + 2hcl (aq)=mgcl2 (aq) + h2 (g)mg(s) + 2hcl(aq) = mgcl2(aq) + h2(g) mg+hci=mgci2+h2mg + 2hci = mgci2 + h2 mg+o2 =mgo2mg + o2 = 2mgo mn+hl = h2+ mnl32mn + 6hl = 3h2 + 2mnl3