Переведите число 34 из десятичной системы счисления в двоичную систему счисления. в ответе укажите двоичное число.

Двоичная система. ответ: 100010

Var a,b0,b1,b2,b3,b4,b5,b6,b7,b8,b9: integer; begin writeln('введите число'); readln(a); while a> 0 do     begin     case a mod 10 of     0: b0: =b0+1;     1: b1: =b1+1;     2: b2: =b2+1;     3: b3: =b3+1;     4: b4: =b4+1;     5: b5: =b5+1;     6: b6: =b6+1;     7: b7: =b7+1;     8: b8: =b8+1;     9: b9: =b9+1;     end;     a: = a div 10;     end; if (b0 = 3)and(b1< 2)and(b2< 2)and(b3< 2)and(b4< 2)and(b5< 2)and(b6< 2)and(b7< 2)and(b8< 2)and(b9< 2)then writeln('верно') else if (b1 = 3)and(b2< 2)and(b3< 2)and(b4< 2)and(b5< 2)and(b6< 2)and(b7< 2)and(b8< 2)and(b9< 2)and(b0< 2)then writeln('верно') else if (b2 = 3)and(b3< 2)and(b4< 2)and(b5< 2)and(b6< 2)and(b7< 2)and(b8< 2)and(b9< 2)and(b0< 2)and(b1< 2)then writeln('верно') else if (b3 = 3)and(b4< 2)and(b5< 2)and(b6< 2)and(b7< 2)and(b8< 2)and(b9< 2)and(b0< 2)and(b1< 2)and(b2< 2)then writeln('верно') else if (b4 = 3)and(b5< 2)and(b6< 2)and(b7< 2)and(b8< 2)and(b9< 2)and(b0< 2)and(b1< 2)and(b2< 2)and(b3< 2)then writeln('верно') else if (b5 = 3)and(b6< 2)and(b7< 2)and(b8< 2)and(b9< 2)and(b0< 2)and(b1< 2)and(b2< 2)and(b3< 2)and(b4< 2)then writeln('верно') else if (b6 = 3)and(b7< 2)and(b8< 2)and(b9< 2)and(b0< 2)and(b1< 2)and(b2< 2)and(b3< 2)and(b4< 2)and(b5< 2)then writeln('верно') else if (b7 = 3)and(b8< 2)and(b9< 2)and(b0< 2)and(b1< 2)and(b2< 2)and(b3< 2)and(b4< 2)and(b5< 2)and(b6< 2)then writeln('верно') else if (b8 = 3)and(b9< 2)and(b0< 2)and(b1< 2)and(b2< 2)and(b3< 2)and(b4< 2)and(b5< 2)and(b6< 2)and(b7< 2)then writeln('верно') else if (b9 = 3)and(b0< 2)and(b1< 2)and(b2< 2)and(b3< 2)and(b4< 2)and(b5< 2)and(b6< 2)and(b7< 2)and(b8< 2)then writeln('верно') else writeln('не верно') end.