X^2-5=(x-5)(2x-1) (3x-1)^2=1 (x+3)(x-4)=-12 (3x-1)^2=4-12x нужно решить

X² - 5 = ( x - 5)(2x - 1) x² - 5 = 2x² - x - 10x + 5 x² - 2x² + x + 10x = 5 + 5 - x² + 11x - 10 = 0 x² - 11x + 10 = 0 d = b² - 4ac = ( - 11)² - 4 × 1 × 10 = 121 - 40 = 81 = 9² x₁ = 11 + 9 / 2 = 10 x₂ = 11 -9 / 2 = 1 ( 3x - 1)² = 1 ( 3x - 1)( 3x - 1) = 1 9x² - 3x - 3x + 1 - 1 = 0 9x² - 6x + 0 = 0 d = b² - 4ac = 36 - 4 × 9 × 0 = 36 = 6² x₁ = 6 + 6 / 18 = 12/18 = 6/9 = 2/3 x₂ = 6 - 6 / 18 = 0 ( x + 3)( x - 4) = -12 x² - 4x + 3x - 12 = - 12 x² - x - 12 + 12 = 0 x² - x + 0 = 0 d = b² - 4ac = 1 - 4 × 1 × 0 = 1 = 1² x₁ = 1 + 1 / 2 = 1 x₂ = 1 - 1 / 2 = 0 ( 3x - 1)² = 4 - 12x (3x - 1)( 3x - 1) = 4 - 12x 9x² - 3x - 3x + 1 = 4 - 12x 9x² - 6x + 1 - 4 + 12x = 0 9x² + 6x - 3 = 0 d = b² - 4ac = 36 - 4 × 9 × ( - 3) = 36 + 108 = 144 = 12² x₁ = - 6 + 12 / 18 = 6 / 18 = 1/3 x₂ = - 6 - 12 / 18 = - 18 / 18 = - 1

ответ:Тогда у =-1

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